0.25x^2+2x-45=0

Solution for 0.25x^2+2x-45=0 equation:

0.25x^2+2x-45=0

a = 0.25; b = 2; c = -45;
Δ = b2-4ac
Δ = 22-4·0.25·(-45)
Δ = 49
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{49}=7$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(2)-7}{2*0.25}=\frac{-9}{0.5}
=-18
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(2)+7}{2*0.25}=\frac{5}{0.5}
=10
$